If it takes total work W to give an object a speed vand kinetic energy K,starting from rest, what will be the object's speed (in terms of v)if we do twice as much work on it, again starting from rest? Round off your result to 1 decimal place. Yanit: square

## Step 1The problem involves the concept of kinetic energy and work done. The kinetic energy (K) of an object is given by the formula:### where is the mass of the object and is its velocity.## Step 2The work done (W) on an object is equal to the change in its kinetic energy. This is based on the work-energy principle.## Step 3If we do twice as much work on the object, the new work done (W') is:### ## Step 4The new kinetic energy (K') of the object is:### \(K' = \frac{1}{2}m(v')^2\)where is the new velocity of the object.## Step 5According to the work-energy principle, the work done is equal to the change in kinetic energy. Therefore, we can write:### ## Step 6Substituting the values of , , and into the equation, we get:### \(2W = \frac{1}{2}m(v')^2 - \frac{1}{2}mv^2\)## Step 7Solving this equation for , we get:###