A hypothetical element, E, has two stable isotopes. E-38=38.012 u 75.68% E-46=45.981u 24.32% The element's atomic mass would be closest to which of the elements? i) K ii) Ar iii ) Ca iv ) Sc v) Cl a. iii b. ii C. V d. i e. iV

Question

A hypothetical element, E, has two stable isotopes. E-38=38.012 u 75.68% E-46=45.981u 24.32% The element's atomic mass would be closest to which of the elements? i) K ii) Ar iii ) Ca iv ) Sc v) Cl a. iii b. ii C. V d. i e. iV

Answer 1

To find the atomic mass of the hypothetical element E, we need to calculate the weighted average of the atomic masses of its isotopes.The atomic mass of E can be calculated using the formula:Atomic mass of E = (fractional abundance of isotope 1 × atomic mass of isotope 1) + (fractional abundance of isotope 2 × atomic mass of isotope 2)Given:Isotope E-38 has an atomic mass of 38.012 u and accounts for 75.68% of the total abundance.Isotope E-46 has an atomic mass of 45.981 u and accounts for 24.32% of the total abundance.Substituting the values into the formula:Atomic mass of E = (0.7568 × 38.012) + (0.2432 × 45.981)Calculating the values:Atomic mass of E = 28.683 + 11.188Atomic mass of E = 39.871Therefore, the atomic mass of the hypothetical element E is approximately 39.871.Comparing this value with the atomic masses of the given elements:i) K (Potassium) has an atomic mass of approximately 39.098.ii) Ar (Argon) has an atomic mass of approximately 39.948.iii) Ca (Calcium) has an atomic mass of approximately 40.078.iv) Sc (Scandium) has an atomic mass of approximately 44.96.v) Cl (Chlorine) has an atomic mass of approximately 35.45.The atomic mass of E (39.871) is closest to the atomic mass of K (Potassium), which is approximately 39.098.Therefore, the correct answer is option d. i.

Soru

A hypothetical element, E, has two stable isotopes. E-38=38.012 u 75.68% E-46=45.981u 24.32% The element's atomic mass would be closest to which of the elements? i) K ii) Ar iii ) Ca iv ) Sc v) Cl a. iii b. ii C. V d. i e. iV

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