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Sqrt((sqrt(3)-2)^2)+sqrt[3](-8)

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sqrt((sqrt(3)-2)^2)+sqrt[3](-8)

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Uzman doğrulaması
Usta · 5 yıl öğretmeni

Cevap

To solve the expression \(\sqrt{(\sqrt{3} - 2)^2} + \sqrt{-8}\), we need to handle each part of the expression separately.First, consider \(\sqrt{(\sqrt{3} - 2)^2}\): Since is less than 2, is negative. Therefore, the absolute value is: Next, consider : Now, combine the results: So, the final answer is: