Soru
11. For the following reaction: P_(2)O_(5)(s)+3H_(2)O(t)arrow 2H_(3)PO_(4)(aq) 288 g of P_(2)O_(5) and 54 g of H_(2)O were supplied. a) Which is the limiting reactant?
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4.3
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Usta · 5 yıl öğretmeni
Uzman doğrulaması
Cevap
To determine the limiting reactant, we need to compare the amount of each reactant available to the amount required by the balanced chemical equation.The balanced chemical equation is:
Given:- 288 g of
- 54 g of
First, we need to calculate the molar masses of
and
:- Molar mass of
= 2(30.97) + 5(16.00) = 141.94 g/mol- Molar mass of
= 2(1.01) + 16.00 = 18.02 g/molNext, we convert the masses of
and
to moles:- Moles of
=
= 2.03 moles- Moles of
=
= 3.00 molesNow, we compare the mole ratio of the reactants to the stoichiometric ratio in the balanced equation:- The balanced equation requires 1 mole of
for every 3 moles of
.We have:- 2.03 moles of
- 3.00 moles of
Since we have more than enough
(3.00 moles) to react with 2.03 moles of
,
is the limiting reactant.Therefore, the limiting reactant is
.