Soru
It is compose d of 40.92 percent carbon (C),4.58 percent hydrogen (H) , and 54.50 percent oxygen (O) by mass. Determine its empirical formula.
Çözüm
4.7
(205 Oylar)
Müge
Elit · 8 yıl öğretmeni
Uzman doğrulaması
Cevap
To determine the empirical formula, we need to find the ratio of the number of atoms of each element in the compound.Given:- 40.92% carbon (C)- 4.58% hydrogen (H)- 54.50% oxygen (O)Step 1: Convert the percentages to grams.- Carbon (C): 40.92 g- Hydrogen (H): 4.58 g- Oxygen (O): 54.50 gStep 2: Calculate the number of moles of each element.- Carbon (C): 40.92 g / 12.01 g/mol = 3.40 mol- Hydrogen (H): 4.58 g / 1.008 g/mol = 4.53 mol- Oxygen (O): 54.50 g / 16.00 g/mol = 3.41 molStep 3: Find the ratio of the number of moles of each element.- Carbon (C): 3.40 mol- Hydrogen (H): 4.53 mol- Oxygen (O): 3.41 molStep 4: Divide each ratio by the smallest number of moles.- Carbon (C): 3.40 mol / 3.40 mol = 1- Hydrogen (H): 4.53 mol / 3.40 mol = 1.33- Oxygen (O): 3.41 mol / 3.40 mol = 1Step 5: Round the ratios to the nearest whole number.- Carbon (C): 1- Hydrogen (H): 1.33 (rounded to 1)- Oxygen (O): 1Therefore, the empirical formula of the compound is C1H1O1.