When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the reaction below. 2H_(2)+O_(2)arrow 2H_(2)O How many grams of oxygen were required? 48.09 0.0469 g 0.0208 g 21.3 g

Question

Answer 1

To determine how many grams of oxygen were required, we need to use stoichiometry based on the balanced chemical equation:

From the equation, 1 mole of

reacts with 2 moles of

to produce 2 moles of

.Given:- 3.00 moles of

- 1.50 moles of

According to the stoichiometry of the reaction, 1.50 moles of

are needed to react with 3.00 moles of

, which is consistent with the given amounts.Now, calculate the mass of 1.50 moles of

:The molar mass of

is approximately 32.00 g/mol.

Therefore, the correct answer is approximately 48.09 g (considering rounding differences).

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