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13) The Reaction CH_(3)-Nequiv Carrow CH_(3)-Cequiv N Is a First-order Reaction . At 2303^circ C.k=6.29ast 10^-4s-1 If [CH_(3)-N=C] Is

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13) The reaction CH_(3)-Nequiv Carrow CH_(3)-Cequiv N is a first-order reaction . At 2303^circ C.k=6.29ast 10^-4s-1 If [CH_(3)-N=C] is 1.00times 10^-3 initially. [CH_(3)-N=Cl __ Mafter 1.000times 10^3s A) 5.33times 10-4 B) 2.34times 10-4 C) 1.88times 10^-3 D) 4.27times 10.3

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4.4 (232 Oylar)
Nihat
Uzman doğrulaması
Usta · 5 yıl öğretmeni

Cevap

To solve this problem, we can use the integrated rate law for a first-order reaction: where:- is the initial concentration of the reactant,- is the concentration of the reactant at time ,- is the rate constant,- is the time.Given:- - - We need to find after .First, calculate the concentration of the reactant remaining after : Now, calculate the concentration of : Therefore, the correct answer is:A)