2. A Carnot heat engine receives heat at the rate of 74,000kJ/min from a high-temperature source at 510^circ C If the maximum possible power output of the engine is 653 kW, find the temperature of the low.temperature sink in which the engine rejects heat (15pts) Assumptions: The system operates steadily.

To find the temperature of the low-temperature sink, we can use the Carnot efficiency equation: where:- is the Carnot efficiency,- is the temperature of the cold reservoir (sink),- is the temperature of the hot reservoir (source).Given:- The heat input rate ( ) is ,- The power output ( ) is ,- The temperature of the hot reservoir ( ) is .First, convert the heat input rate to power: The Carnot efficiency is also given by: Substitute the given values: Now, use the Carnot efficiency equation to find : Rearrange to solve for : Convert to Kelvin: Now, calculate : Convert back to Celsius: Therefore, the temperature of the low-temperature sink is approximately .