Element: Mg of Atoms:1 Element: CI of Atoms: 2 gram formula weight (g):95.21 Compound Formula: C_(6)H_(12)O_(6) Element: C of Atoms: square Element: H of Atoms: square : Element: 0 of Atoms: square gram formula weight (g): square Assignment -12. How Big Is a Mole? Avogadro's Number

Let's break down the information and fill in the blanks step by step.1. **Compound Formula: ** - Element: C (Carbon) - Number of Atoms: 6 - Element: H (Hydrogen) - Number of Atoms: 12 - Element: O (Oxygen) - Number of Atoms: 62. **Gram Formula Weight Calculation for :** To calculate the gram formula weight (molar mass) of , we need to sum up the atomic masses of all the atoms in the compound. The atomic masses are approximately: - Carbon (C): 12.01 g/mol - Hydrogen (H): 1.01 g/mol - Oxygen (O): 16.00 g/mol Now, calculate the total molar mass: So, the completed information is:- Compound Formula: - Element: C - Number of Atoms: 6 - Element: H - Number of Atoms: 12 - Element: O - Number of Atoms: 6 - Gram Formula Weight (g): 180.183. **Assignment - How Big Is a Mole? Avogadro's Number**Avogadro's number is . This number represents the number of atoms, molecules, or particles in one mole of a substance. It is a fundamental constant in chemistry used to convert between the number of particles and the amount of substance in moles.