Factorise using the difference between two squares: (x+2)^2-4 (x-3)^2-36 100-(x-11)^2 81-(x-8)^2 (x+7)^2-1 f 9-(x+4)^2 Answer the Opening Problem on page 208. 7 Factorise using the difference between two squares: (x+3)^2-(x-1)^2 (2x-1)^2-(x+1)^2 (1-3x)^2-(2x+1)^2

Question

Factorise using the difference between two squares: (x+2)^2-4 (x-3)^2-36 100-(x-11)^2 81-(x-8)^2 (x+7)^2-1 f 9-(x+4)^2 Answer the Opening Problem on page 208. 7 Factorise using the difference between two squares: (x+3)^2-(x-1)^2 (2x-1)^2-(x+1)^2 (1-3x)^2-(2x+1)^2

Answer 1

Let's factorize each expression using the difference of squares formula, which states that \(a^2 - b^2 = (a + b)(a - b)\).1. \((x+2)^{2} - 4\) Here,

and

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2. \((x-3)^{2} - 36\) Here,

and

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3. \(100 - (x-11)^{2}\) Here,

and

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4. \(81 - (x-8)^{2}\) Here,

and

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5. \((x+7)^{2} - 1\) Here,

and

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6. \(9 - (x+4)^{2}\) Here,

and

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7. \((x+3)^{2} - (x-1)^{2}\) Here,

and

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8. \(({2} - (x+1)^{2}\) Here,

and

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9. \((1-3x)^{2} - (2x+1)^{2}\) Here,

and

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So, the factorized forms are:1. \((x+4)(x)\)2. \((x+3)(x-9)\)3. \((x-1)(19-x)\)4. \((x-1)(17-x)\)5. \((x+8)(x+6)\)6. \((x+7)(-x-1)\)7. \(2(x+1)(x+2)\)8. \(3x(x-2

Soru

Factorise using the difference between two squares: (x+2)^2-4 (x-3)^2-36 100-(x-11)^2 81-(x-8)^2 (x+7)^2-1 f 9-(x+4)^2 Answer the Opening Problem on page 208. 7 Factorise using the difference between two squares: (x+3)^2-(x-1)^2 (2x-1)^2-(x+1)^2 (1-3x)^2-(2x+1)^2

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