29) A solution is prepared by dissolving 0.60 g of nicotine (a nonelectrolyte) in water to make 12 mL of solution. The osmotic pressure of the solution is 765.00kPa at 25^circ C The molecular weight of nicotine is g/mol A) 28 B) 43 C) 50 D) 160 E) 0.60 Answer: D

To solve this problem, we need to use the formula for osmotic pressure: Where:- is the osmotic pressure (in kPa)- is the number of moles of solute- is the volume of the solution (in liters)- is the ideal gas constant (in kPa·L/mol·K)- is the temperature (in Kelvin)Given:- - - - First, we need to find the number of moles of nicotine ( ) using the osmotic pressure formula: Substitute the given values into the equation: Next, we need to find the molecular weight of nicotine. The molecular weight (MW) is the mass of the solute divided by the number of moles: Given that the mass of nicotine is : Therefore, the molecular weight of nicotine is approximately .The correct answer is:D) 160