41 - (CHEMI/12, HL. Summer 2022.02) - Stoichiomeric Relationship 30g of an organic compound produces 44g CO_(2) and 18g H_(2)O as the only combustion products. Which of the following is the empirical formula for this compound? M_(r)CO_(2)=44M_(r)H_(2)O=18 A.) CH_(2) B. CH_(3) CHO D. CH_(2)O

To find the empirical formula of the compound, we need to determine the moles of carbon and hydrogen present in the compound.Given:- 30g of the organic compound produces 44g of and 18g of .First, let's calculate the moles of carbon in the compound:- The molar mass of is 44 .- The moles of produced is 44g / 44 = 1 mole.Since each mole of contains one mole of carbon, the moles of carbon in the compound is also 1 mole.Next, let's calculate the moles of hydrogen in the compound:- The molar mass of is 18 .- The moles of produced is 18g / 18 = 1 mole.Since each mole of contains two moles of hydrogen, the moles of hydrogen in the compound is 2 moles.Now, let's determine the empirical formula:- The empirical formula is the simplest whole number ratio of the moles of each element in the compound.- The ratio of carbon to hydrogen is 1:2.Therefore, the empirical formula for this compound is .So, the correct answer is:A.)