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mass box a=10grams mass box b=5 grams; mass box c -made of one a and one b how many grams of a would be needed to give the same number

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Mass box A=10grams Mass box B=5 grams; Mass box C -made of one A and one B How many grams of A would be needed to give the same number of particles: : as 7.5 grams of B? square i as 2.5 grams? square as 12.5 grams? square as 1 gram? square

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To solve this problem, we need to understand the relationship between the masses of boxes A and B and how they relate to the number of particles.Given:- Mass of box A = 10 grams- Mass of box B = 5 gramsWe assume that the number of particles is directly proportional to the mass. Therefore, if you have a certain mass of B, you can find the equivalent mass of A that contains the same number of particles by setting up a proportion.1. **As 7.5 grams of B:** Since 5 grams of B is equivalent to 10 grams of A (because one B is half the mass of one A), we set up the proportion: Solving for : 2. **As 2.5 grams of B:** Using the same method: Solving for : 3. **As 12.5 grams of B:** Again, using the proportion: Solving for : 4. **As 1 gram of B:** Finally, for 1 gram of B: Solving for : Therefore, the answers are:- As 7.5 grams of B: 15 grams of A- As 2.5 grams of B: 5 grams of A- As 12.5 grams of B: 25 grams of A- As 1 gram of B: 2 grams of A