A particle rotates in a circle of radius 430 m. Ata particular instant its acceleration is 1.05m/s^2 in a direction that makes an angle of 38.0^circ to its direction of motion Determine its speed at this moment. v=1.67m/s Previous Answers correct Part B Determine its speed 230 s later, assuming constant tangential acceleration. ? v=1.90 Submit Previous Answers Request Answer & Incorrect; Try Again;4 attempts remaining Nex

Question

Answer 1

To determine the speed of the particle 230 seconds later, assuming constant tangential acceleration, we can use the following formula:

where:-

is the final velocity-

is the initial velocity-

is the tangential acceleration-

is the timeGiven that the particle's acceleration is

in a direction that makes an angle of

to its direction of motion, we can calculate the tangential acceleration as:

Assuming the particle starts from rest, the initial velocity

is

. The time

is given as

.Substituting the values into the formula, we get:

Calculating this expression gives us the speed of the particle 230 seconds later, assuming constant tangential acceleration.

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