Soru
21) What is the molarity of sodium chloride in solution that is 13.0% by mass sodium chloride and that has a density of 1.10g/mL 7 A) 143 B) 2.45 C) 2.56 D) 2.23 E) 1.43times 10^-2 Answer:B
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To find the molarity of sodium chloride in the solution, we need to follow these steps:1. Calculate the mass of sodium chloride in 1 liter of the solution.2. Convert the mass of sodium chloride to moles.3. Calculate the molarity using the formula: Molarity = moles of solute / liters of solution.Given information:- The solution is 13.0% by mass sodium chloride.- The density of the solution is 1.10 g/mL.Step 1: Calculate the mass of sodium chloride in 1 liter of the solution.Density = 1.10 g/mLVolume of the solution = 1 liter = 1000 mLMass of the solution = Density × Volume = 1.10 g/mL × 1000 mL = 1100 gMass of sodium chloride = 13.0% of 1100 g = 0.13 × 1100 g = 143 gStep 2: Convert the mass of sodium chloride to moles.Molar mass of sodium chloride (NaCl) = 58.44 g/molMoles of sodium chloride = Mass of sodium chloride / Molar mass of sodium chlorideMoles of sodium chloride = 143 g / 58.44 g/mol = 2.44 molStep 3: Calculate the molarity using the formula:Molarity = Moles of solute / Liters of solutionMolarity = 2.44 mol / 1 L = 2.44 MTherefore, the molarity of sodium chloride in the solution is 2.44 M.The correct answer is B) 2.4 M.