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check should 16.3 g of s contain fewer than avogadro's number of atoms? what mass of s would contain avogadro's number of atoms?

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Check Should 16.3 g of S contain fewer than Avogadro's number of atoms? What mass of S would contain Avogadro's number of atoms?

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1. Yes, 16.3 g of sulfur contains fewer than Avogadro's number of atoms.2. The mass of sulfur that contains Avogadro's number of atoms is approximately g.

Daha Fazla

## Step 1The problem involves the concept of Avogadro's number, which is a fundamental constant in chemistry. Avogadro's number, denoted as , is approximately . This number represents the number of atoms in one mole of any substance.## Step 2The molar mass of an element is the mass of one mole of that element. For sulfur (S), the molar mass is approximately 32 g/mol.## Step 3To find out if 16.3 g of sulfur contains fewer than Avogadro's number of atoms, we need to compare the given mass with the molar mass of sulfur. Since 16.3 g is less than 32 g, it contains fewer than Avogadro's number of atoms.## Step 4To find the mass of sulfur that contains Avogadro's number of atoms, we multiply the molar mass of sulfur by Avogadro's number. This gives us g, which is approximately g.