A hypothetical element, E has two stable isotopes. E-38=38.012u 75.68% E-46=45.981u 24.32% The element's atomic mass would be closest to which of the elements? i) K ii) Ar iii Ca iv ) Sc V ) Cl a. iii b. overrightarrow (n) c. surd d. overrightarrow (i) e N

Question

A hypothetical element, E has two stable isotopes. E-38=38.012u 75.68% E-46=45.981u 24.32% The element's atomic mass would be closest to which of the elements? i) K ii) Ar iii Ca iv ) Sc V ) Cl a. iii b. overrightarrow (n) c. surd d. overrightarrow (i) e N

Answer 1

To find the atomic mass of element E, we need to calculate the weighted average of the atomic masses of its isotopes.The weighted average is calculated by multiplying the atomic mass of each isotope by its respective abundance (expressed as a decimal) and then summing up these values.For isotope E-38:Atomic mass = 38.012uAbundance = 75.68% = 0.7568Weighted average contribution = 38.012u * 0.7568 = 28.82uFor isotope E-46:Atomic mass = 45.981uAbundance = 24.32% = 0.2432Weighted average contribution = 45.981u * 0.2432 = 11.18uNow, we add up the weighted average contributions of both isotopes to find the atomic mass of element E:Atomic mass of E = 28.82u + 11.18u = 40.00uComparing the atomic mass of element E (40.00u) with the atomic masses of the given elements:i) K = 39.10uii) Ar = 39.95uiii) Ca = 40.08uiv) Sc = 44.96uv) Cl = 35.45uThe atomic mass of element E (40.00u) is closest to the atomic mass of calcium (Ca) with an atomic mass of 40.08u.Therefore, the correct answer is:a.

Soru

A hypothetical element, E has two stable isotopes. E-38=38.012u 75.68% E-46=45.981u 24.32% The element's atomic mass would be closest to which of the elements? i) K ii) Ar iii Ca iv ) Sc V ) Cl a. iii b. overrightarrow (n) c. surd d. overrightarrow (i) e N

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