A particle starting from rest revolves with uniformly increasing speed in a clockwise circle in the zy plane. The center of the circle is at the origin of an xy coordinate system. Att=0 the particle is at x=0.0,y=2.9mcdot Att=1.0s it has made one. quarter of a revolution and is at x=y_(0),y=0.0 Part A Determine its speed at 1.0 s Express your answer to two significant figures and include e the appropriate units. ? m v=3.35 square Submit Previous Answers Request Answer Incorrect; Try Ağain;4 attempts remaining

To determine the speed of the particle at 1.0 s, we need to use the relationship between velocity and angular displacement in circular motion.Given:- The particle starts from rest, so its initial velocity .- At , the particle is at \( (x_0, y_0) = (0, 2.9 \, \text{m}) \).- At , the particle is at \( (x, y) = (y_0, 0) \).Since the particle makes one-quarter of a revolution in 1.0 s, the angular displacement is or radians.The relationship between linear velocity , angular velocity , and radius is: The angular velocity can be found using the formula: Here, radians and : The radius of the circle is the distance from the origin to the initial position of the particle: Now, we can find the speed : Therefore, the speed of the particle at 1.0 s is approximately .