The number of water molecules present in a drop of water (volume 0.0018^1t ml) at room temperature is (d=1g/ml) ?

Question

The number of water molecules present in a drop of water (volume 0.0018^1t ml) at room temperature is (d=1g/ml) ?

Answer 1

To find the number of water molecules in a drop of water, we need to calculate the mass of the water and then use Avogadro's number to find the number of molecules.Given:Volume of water = 0.0018 mlDensity of water (d) = 1 g/mlStep 1: Calculate the mass of water.Mass of water = Volume of water * Density of waterMass of water = 0.0018 ml * 1 g/mlMass of water = 0.0018 gStep 2: Calculate the number of water molecules.Number of water molecules = Mass of water / Molar mass of waterNumber of water molecules = 0.0018 g / 18.015 g/molNumber of water molecules ≈ 9.89 x 10^21 moleculesTherefore, the number of water molecules present in a drop of water at room temperature is approximately 9.89 x 10^21 molecules.

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The number of water molecules present in a drop of water (volume 0.0018^1t ml) at room temperature is (d=1g/ml) ?

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