Balance the following reaction A coefficient of "I"is understood. Choose option "blank" for the correct answer if the coefficient is "1." KI+ Alb(NO_(3))_(2)arrow Albl_(2)+ AlCNO_(3)

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's break it down step-by-step:The unbalanced equation is: 1. **Balance Aluminum (Al):** There is 1 Al atom on both sides, so aluminum is already balanced.2. **Balance Iodine (I):** On the left side, there is 1 iodine atom in KI. On the right side, there are 2 iodine atoms in AlI₂. To balance iodine, place a coefficient of 2 in front of KI: 3. **Balance Potassium (K):** Now, there are 2 potassium atoms on the left side (from 2 KI). Therefore, place a coefficient of 2 in front of KNO₃ on the right side: 4. **Balance Nitrate (NO₃):** On the left side, there are 2 nitrate groups from Al(NO₃)₂. On the right side, there are 2 nitrate groups from 2 KNO₃. The nitrates are balanced.Now, the balanced equation is: In terms of coefficients, they are:- KI: 2- Al(NO₃)₂: 1 (blank)- AlI₂: 1 (blank)- KNO₃: 2So, the correct answer with blanks for coefficients of 1 is: