Soru
24-6 Calculate the frequency in hertz of (a) an X-ray beam with a wavelength of 2.65stackrel (circ )(A) (b) an emission line for copper at 211.0 nm. (c)the line at 694.3 nm produced by a ruby laser (d) the output of a CO_(2) laser at 10.6 jim. (e)an infrared absorption peak at 19.6 um. (f) a microwave beam at 1.86 cm.
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4.6
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Elit · 8 yıl öğretmeni
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Cevap
To calculate the frequency of a wave, we can use the formula:Frequency (f) = Speed of light (c) / Wavelength (λ)Where:- The speed of light (c) is approximately 3.00 x 10^8 m/s.- The wavelength (λ) is given in nanometers (nm) for parts (b), (c), (d), and (e), and in angstroms (Å) for part (a).Let's calculate the frequency for each part:(a) An X-ray a wavelength of 2.65Å:Frequency (f) = Speed of light (c) / Wavelength (λ)Frequency (f) = (3.00 x 10^8 m/s) / (2.65 x 10^-10 m)Frequency (f) = 1.13 x 10^19 Hz(b) An emission line for copper at 211.0 nm:Frequency (f) = Speed of light (c) / Wavelength (λ)Frequency (f) = (3.00 x 10^8 m/s) / (211.0 x 10^-9 m)Frequency (f) = 1.42 x 10^15 Hz(c) The line at 694.3 nm produced by a ruby laser:Frequency (f) = Speed of light (c) / Wavelength (λ)Frequency (f) = (3.00 x 10^8 m/s) / (694.3 x 10^-9 m)Frequency (f) = 4.32 x 10^14 Hz(d) The output of a CO2 laser at 10.6 μm:Frequency (f) = Speed of light (c) / Wavelength (λ)Frequency (f) = (3.0010^8 m/s) / (10.6 x 10^-6 m)Frequency (f) = 2.83 x 10^13 Hz(e) An infrared absorption peak at 19.6 μm:Frequency (f) = Speed of light (c) / Wavelength (λ)Frequency (f) = (3.00 x 10^8 m/s) / (19.6 x 10^-6 m)Frequency (f) = 1.53 x 10^13 Hz(f) A microwave beam at 1.86 cm:Frequency (f) = Speed of light (c) / Wavelength (λ)Frequency (f) =.00 x 10^8 m/s) / (1.86 x 10^-2 m)Frequency (f) = 1.62 x 10^10 HzTherefore, the frequencies for each part are:(a) 1.13 x 10^19 Hz(b) 42 x 10^15 Hz(c) 4.32 x 10^14 Hz(d) 2.83 x 10^13 Hz(e) 1.53 x 10^13 Hz(f) 1.62 x 10^10 Hz