What is the output of the following code? x=10 def my function(): x=20 print(x) my function() print (x) error 10 . 20 20 , 10 20 , 20

Question

What is the output of the following code? x=10 def my function(): x=20 print(x) my function() print (x) error 10 . 20 20 , 10 20 , 20

Answer 1

The output of the code is:```2020```Explanation:1. The variable `x` is initially assigned the value `10`.2. The function `my_function` is defined, of `x` to `20` within the function's scope.3. When `my_function` is called, it prints the value of `x` inside the function, which is `20`.4. After the function call, the value of `x` outside the function remains unchanged at `10`, so the final print statement outputs `20`.

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What is the output of the following code? x=10 def my function(): x=20 print(x) my function() print (x) error 10 . 20 20 , 10 20 , 20

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