Exercise 2 Natural copper is composed of two different isotopes. Their masses are 62.929 and 64.92 , respectively. The stomic number of copper is Z=29 2. Give the composition of the two isotopes. b. Knowing that the atomic mass of the natural mixture of the two isotopes is 6354, calculate the abundance of each isotope.

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Exercise 2 Natural copper is composed of two different isotopes. Their masses are 62.929 and 64.92 , respectively. The stomic number of copper is Z=29 2. Give the composition of the two isotopes. b. Knowing that the atomic mass of the natural mixture of the two isotopes is 6354, calculate the abundance of each isotope.

Answer 1

Let's denote the abundance of the isotope with mass 62.929 as x and the abundance of the isotope with mass 64.92 as (1-x) since the total abundance of the two isotopes is 100%.The atomic mass of the natural mixture can be calculated using the formula:Atomic mass = (mass of isotope 1 * abundance of isotope 1) + (mass of isotope 2 * abundance of isotope 2)Given that the atomic mass of the natural mixture is 63.54, we can set up the equation:63.54 = (62.929 * x) + (64.92 * (1-x))Solving for x, we get:63.54 = 62.929x + 64.92 - 64.92x63.54 - 64.92 = -1.973x-1.372 = -1.973xx = 1.973 / 1.973x = 1Therefore, the abundance of the isotope with mass 62.929 is 100%, and the abundance of the isotope with mass 64.92 is 0%.

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