45 - (CHEMI/10.HL. Winter 2022 (Q3) - Stoichiometric Relationship How many moles of carbon dioxide are produced by the complete combustion of 7.0 g of ethene, C_(2)H_(4)(g) M_(r)=28 A. 0.25 B. 0.5 C. 0.75 D. 1.0

To find the number of moles of carbon dioxide produced by the complete combustion of 7.0 g of ethene, we need to use the stoichiometric relationship between the reactants and products in the balanced chemical equation for the combustion of ethene.The balanced chemical equation for the complete combustion of ethene is: From the balanced equation, we can see that 1 mole of ethene reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide.Given that the molar mass of ethene ( ) is 28 g/mol, we can calculate the number of moles of ethene in 7.0 g:Number of moles of ethene = According to the balanced equation, 1 mole of ethene produces 2 moles of carbon dioxide. Therefore, 0.25 moles of ethene will produce:Number of moles of carbon dioxide = Therefore, the correct answer is B. 0.5 moles of carbon dioxide are produced by the complete combustion of 7.0 g of ethene.