If the density of lead is 11.34g/cm^3 how many atoms are in a lead with a volume of 40cm^3 a. 1.32times 10^24 b. 1.16times 10^22 C. 1.16times 10^23 d. 6.6times 10^23 e. 1.32times 10^23

To find the number of atoms in a lead with a volume of 40 cm³, we need to use the given density of lead, which is 11.34 g/cm³.First, we can calculate the mass of the lead using the formula:mass = density × volumemass = 11.34 g/cm³ × 40 cm³mass = 453.6 gNext, we need to find the number of moles of lead in the given mass. We can use the molar mass of lead, which is 207.2 g/mol.moles of lead = mass / molar massmoles of lead = 453.6 g / 207.2 g/molmoles of lead ≈ 2.18 molFinally, we can calculate the number of atoms using Avogadro's number, which is 6.022 × 10²³ atoms/mol.number of atoms = moles of lead × Avogadro's numbernumber of atoms = 2.18 mol × 6.022 × 10²³ atoms/molnumber of atoms ≈ 1.32 × 10²³ atomsTherefore, the correct answer is option e.