2. A man with type AB blood is married to a woman also with type AB blood. What proportion of their children will have: Show the cross: A blood? B blood? Oblood AB blood A man with type B blood (genotype BB is married to a woman with type O blood. Show the cross: Vhat proportion of their children will have: A blood? B blood? Oblood AB blood

Question

2. A man with type AB blood is married to a woman also with type AB blood. What proportion of their children will have: Show the cross: A blood? B blood? Oblood AB blood A man with type B blood (genotype BB is married to a woman with type O blood. Show the cross: Vhat proportion of their children will have: A blood? B blood? Oblood AB blood

Answer 1

1. For the first scenario, the proportion of children with blood type A is 1/4, blood type B is 1/4, blood type O is 0, and blood type AB is 1/2.2. For the second scenario, the proportion of children with blood type A is 0, blood type B is 1, blood type O is 1, and blood type AB is 0.

Answer 2

## Step 1The problem involves understanding the inheritance of blood types in humans. The ABO blood group system is determined by the ABO gene, which has three alleles:

,

, and

. The

and

alleles are co-dominant, meaning that if both are present, they will both be expressed. The

allele is recessive and will only be expressed if no

or

alleles are present.## Step 2For the first scenario, both parents have type AB blood. This means they each have one

and one

allele. When they have children, each child will receive one allele from each parent. This can result in four possible combinations:

,

, and

. These correspond to blood types A, AB, B, and AB respectively. Therefore, the probability of a child having blood type A, B, O, or AB is 1/4, 1/4, 0, and 1/2 respectively.## Step 3For the second scenario, one parent has type B blood (genotype BB) and the other has type O blood (genotype ii). When they have children, each child will receive one allele from each parent. This can result in two possible combinations:

and

. These correspond to blood types B and O respectively. Therefore, the probability of a child having blood type A, B, O, or AB is 0, 1, 1, and 0 respectively.

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