Soru
A person jumps vertically from rest off a diving board that is 5 m above the surface of a deep pool The person's speed reaches zero 2 in below the surface of the pool Find the magnitude of the acceleration of the person while in the water, assuming that it remains cominam!
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4.4
(273 Oylar)
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Usta · 5 yıl öğretmeni
Uzman doğrulaması
Cevap
To find the magnitude of the acceleration of the person while in the water, we can use the kinematic equation:v^2 = u^2 + 2aswhere:v = final velocity (0 m/s, since the speed reaches zero)u = initial velocity (unknown)a = acceleration (what we need to find)s = displacement (2 m, since the speed reaches zero 2 m below the surface of the pool)Since the person's speed reaches zero, we can use the equation:v^2 = u^2 + 2as0 = u^2 + 2a(2)0 = u^2 + 4aWe need to find the initial velocity (u) to solve for the acceleration (a). We can use the equation:v^2 = u^2 + 2as0 = u^2 + 4aSince the person jumps vertically from rest off a diving board that is 5 m above the surface of a deep pool, we can use the equation:v^2 = u^2 + 2as0 = u^2 + 2a(5)0 = u^2 + 10aWe have two equations:0 = u^2 + 4a0 = u^2 + 10aWe can solve these two equations simultaneously to find the acceleration (a).Subtracting the first equation from the second equation, we get:0 - 0 = (u^2 + 10a) - (u^2 + 4a)0 = 6aa = 0 m/s^2Therefore, the magnitude of the acceleration of the person while in the water is 0 m/s^2.