A box is sliding on the frictionless floor through a displacement d=(5m)i+(4m)j while a constant force F=(5N)i+(4N)j acts on the box. If the box has kinetic energy 15J at the beginning of displacement d, what is its kinetic energy at the end of displacement d? Select one: a. 26J b. 6 C. 24 d. 0J e. 56J

To find the kinetic energy of the box at the end of displacement d, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.The work done on the box is given by the dot product of the force and the displacement: Substituting the given values: The initial kinetic energy of the box is given as 15J. Therefore, the change in kinetic energy is: So, the kinetic energy of the box at the end of displacement d is: Therefore, the correct answer is:a. 26J