Question 5. An electrical heater having a resistance of 2Omega is connected to a direct source of 10V Find a.The power of the electric heater. (5p) b. Find the electrical energy dissipated in 3 seconds. (5p)

a. The power of the electric heater can be calculated using the formula: where is the power, is the voltage, and is the resistance.Given that the resistance is and the voltage is , we can substitute these values into the formula: Therefore, the power of the electric heater is .b. The electrical energy dissipated in 3 seconds can be calculated using the formula: where is the energy, is the power, and is the time.Given that the power is and the time is seconds, we can substitute these values into the formula: Therefore, the electrical energy dissipated in 3 seconds is .