11. C. (Chong/this 1111.500.000.000.000.000.000.000.000.10.000.000. 0.02 mol of zine is added to 10.0cm^3 or 1.0moldm^-3 hydrochloric acid. Aln(s)+2NCl(aq)arrow V_(2)Cl_(2)(aq)+N_(2)(g) How many moles of hydrogen are produced? A 0.005 B.0.01 C.0.02 D. 0.04

To solve this problem, we need to use the balanced chemical equation provided: From the balanced equation, we can see that 1 mole of zinc (Zn) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of hydrogen gas (H₂).Given:- 0.02 moles of zinc (Zn)- The concentration of hydrochloric acid (HCl) is , which means there are of HCl in every (or ) of solution.First, we need to determine the volume of hydrochloric acid required to react with 0.02 moles of zinc. Since the reaction requires 2 moles of HCl for every mole of Zn, we need: Next, we calculate the volume of hydrochloric acid needed to provide 0.04 moles of HCl. Given the concentration of : Since , the volume in cm³ is: We are given that we have of hydrochloric acid. Since the available volume of hydrochloric acid (10.0 cm³) is less than the required volume (40 cm³), the limiting reagent is hydrochloric acid.Therefore, the amount of hydrogen gas produced is determined by the amount of hydrochloric acid available. Since we have of hydrochloric acid, we need to find out how much zinc is required to completely react with this amount of hydrochloric acid.From the balanced equation, 2 moles of HCl produce 1 mole of H₂. Therefore, 10.0 cm³ of 1.0 mol/dm³ HCl contains: Since 2 moles of HCl produce 1 mole of H₂, 0.01 moles of HCl will produce: Thus, the number of moles of hydrogen gas produced is: So, the correct answer is A. 0.005.