4 The equation for a reaction that can be used to manufacture lithium carbonate is 2Li_(2)O_(2)+2CO_(2)arrow 2Li_(2)CO_(3)+O_(2) What is the atom economy for this reaction? A 58.9 B 62.1 C 69.8 (D) 82,2 11

To calculate the atom economy for the given reaction, we need to follow these steps:1. Determine the molecular formula for each reactant and product.2. Calculate the molar mass of each reactant and product.3. Calculate the total mass of all reactants and the total mass of all products.4. Calculate the atom economy using the formula: Atom Economy = (Total mass of desired product / Total mass of all reactants) x 100%.Let's go through these steps for the given reaction:1. Reactants: and - : Lithium (Li), Oxygen (O) - : Carbon (C), Oxygen (O) Products: and - : Lithium (Li), Carbon (C), Oxygen (O) - : Oxygen (O)2. Molar masses: - : (2 x 6.94) + (2 x 16) = 13.88 + 32 = 45.88 g/mol - : 12.01 + (2 x 16) = 12.01 + 32 = 44.01 g/mol - : (2 x 6.94) + 12.01 + (3 x 16) = 13.88 + 12.01 + 48 = 73.89 g/mol - : 2 x 16 = 32 g/mol3. Total mass of all reactants: - Total mass of : 2 x 45.88 = 91.76 g/mol - Total mass of : 2 x 44.01 = 88.02 g/mol - Total mass of all reactants = 91.76 + 88.02 = 179.78 g/mol4. Total mass of all products: - Total mass of : 2 x 73.89 = 147.78 g/mol - Total mass of : 1 x 32 = 32 g/mol - Total mass of all products = 147.78 + 32 = 179.78 g/mol5. Atom economy: - Atom economy = (Total mass of desired product / Total mass of all reactants) x 100% - Atom economy = (147.78 / 179.78) x 100% = 82.2%Therefore, the correct answer is (D) 82.2.