When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react,they form 3.00 moles of water according to the reaction below. 2H_(2)+O_(2)arrow 2H_(2)O How many grams of hydrogen were required to form 3.00 moles of water? 0.0469 g 1.49 g 0.672 g 6.05 g

To determine how many grams of hydrogen were required to form 3.00 moles of water, we need to follow these steps:1. **Understand the Reaction**: The balanced chemical equation is: This means 2 moles of react with 1 mole of to produce 2 moles of .2. **Determine Moles of Hydrogen Used**: According to the stoichiometry of the reaction, forming 2 moles of water requires 2 moles of hydrogen. Therefore, forming 3 moles of water would require: 3. **Calculate Mass of Hydrogen**: The molar mass of hydrogen ( ) is approximately 2.02 g/mol. Therefore, the mass of 3 moles of hydrogen is: Thus, the correct answer is approximately 6.05 g (considering rounding differences). Therefore, the closest option is:6.05 g