A projectile is launched from ground level with an initial velocity of y_(0) feel pen second. Neglecting sir resistance, its height in feel I seconds short tourch is given by s=-16t^2+v_(0)t Find the time(s) that the projectle will (8) reach a height of 80 it and (b) return to the ground when vo feel per swared. (a) Find the time(s)that the projectle will reach a height of 80 it; when v_(0)=96 leaf per second. Select the connect choice below and,if necessary, I'd in the answer box to complete your choice. (A) A. square seconds (Use a comma to separate answers at neededs OB. The projectile does not reach 50 feet.

To find the time(s) that the projectile will reach a height of 80 feet, we need to solve the equation for when .Given that feet per second, we can substitute these values into the equation: Rearranging the equation, we have: This is a quadratic equation in the form of , where , , and . We can solve this equation using the quadratic formula: Plugging in the values, we get: Simplifying further, we have: This gives us two possible solutions for : Therefore, the projectile will reach a height of 80 feet at second and seconds.So, the correct answer is (A) 1, 5 seconds.