Study Area Document Sharing User Settings A particle starting from rest revolves with uniformly increasing speed in a clockwise circle in the xy plane The center of the circle is at the origin of an zy coordinate system. Att=0 the particle is at x=0.0,y=2.9mAtt=1.0 s, it has made one- quarter of a revolution and is at x=y_(0),y=0.0 Part A Part B - Part C Determine the average ac acceleration vector during this interval Express your answer using two significant figures. Enter the and y components of the acceleration comma. (-7 ? a_(av)=(4.6,0) Submit Previous Answers RequestAnswer & Incorrect; Try Again;3 attempts remaining Provide Feedback

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Study Area Document Sharing User Settings A particle starting from rest revolves with uniformly increasing speed in a clockwise circle in the xy plane The center of the circle is at the origin of an zy coordinate system. Att=0 the particle is at x=0.0,y=2.9mAtt=1.0 s, it has made one- quarter of a revolution and is at x=y_(0),y=0.0 Part A Part B - Part C Determine the average ac acceleration vector during this interval Express your answer using two significant figures. Enter the and y components of the acceleration comma. (-7 ? a_(av)=(4.6,0) Submit Previous Answers RequestAnswer & Incorrect; Try Again;3 attempts remaining Provide Feedback

Answer 1

To determine the average acceleration vector during the given time interval, we need to find the change in velocity and divide it by the time taken.Given:Initial position at t=0: (x0, y0) = (0, 2.9)Final position at t=1.0 s: (x1, y1) = (2.9, 0)Step 1: Calculate the initial and final velocities.Initial velocity (v0) can be calculated using the formula:v0 = (x1 - x0) / (t1 - t0), (y1 - y0) / (t1 - t0)v0 = (2.9 - 0) / (1.0 - 0), (0 - 2.9) / (1.0 - 0)v0 = (2.9, -2.9) m/sFinal velocity (v1) can be calculated using the formula:v1 = (x2 - x1) / (t2 - t1), (y2 - y1) / (t2 - t1)v1 = (0 - 2.9) / (1.0 - 1.0), (2.9 - 0) / (1.0 - 1.0)v1 = (-2.9, 2.9) m/sStep 2: Calculate the change in velocity.Δv = v1 - v0Δv = (-2.9 - 2.9, 2.9 - (-2.9))Δv = (-5.8, 5.8) m/sStep 3: Calculate the time interval.Δt = t2 - t1Δt = 1.0 - 0Δt = 1.0 sStep 4: Calculate the average acceleration.a_avg = Δv / Δta_avg = (-5.8 / 1.0, 5.8 / 1.0)a_avg = (-5.8, 5.8) m/s²Therefore, the average acceleration vector during this interval is (-5.8, 5.8) m/s².

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