4. Two children weigh 300N and 400N, they sit 2m and 3m away from the pivot (center on the same side of the see-saw. What is their fotal moment? a. 1700Nm 1800Nm c 2200Nm d. 3500Nm friend joins the two children (05) and sits on the other end of the secrsas He weighs 600N How far from the pivot must hesit to balance the see-saw? a 2m h. 2.5m c. 3m d. 5m 6. A moment of 80Nm is noeded to undo a wheel nut The spanner is 20cm long.What force is needed? a- 4N b. 80N c. 400N d. 800N

Question

4. Two children weigh 300N and 400N, they sit 2m and 3m away from the pivot (center on the same side of the see-saw. What is their fotal moment? a. 1700Nm 1800Nm c 2200Nm d. 3500Nm friend joins the two children (05) and sits on the other end of the secrsas He weighs 600N How far from the pivot must hesit to balance the see-saw? a 2m h. 2.5m c. 3m d. 5m 6. A moment of 80Nm is noeded to undo a wheel nut The spanner is 20cm long.What force is needed? a- 4N b. 80N c. 400N d. 800N

Answer 1

4. The total moment is the sum of the moments of each child. The moment is calculated by multiplying the weight of the child by the distance from the pivot. For the first child, the moment is 300N * 2m = 600Nm. For the second child, the moment is 400N * 3m = 1200Nm. The total moment is 600Nm + 1200Nm = 1800Nm. Therefore, the correct answer is b.

.5. To balance the see-saw, the total moment on both sides must be equal. The total moment of the two children is 1800Nm. The friend must sit such that his moment is also 1800Nm. The moment is calculated by multiplying the weight of the friend by the distance from the pivot. Therefore, the distance is 1800Nm / 600N = 3m. Therefore, the correct answer is c. 3m.6. The moment is the product of the force and the distance. The force is calculated by dividing the moment by the distance. Therefore, the force is 80Nm / 0.2m = 400N. Therefore, the correct answer is c. 400N.

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