). The most stable resonance coutributor of this would be: (LO.J) H_(2)C-HC=CH-ddot (O)( A. H_(2)C-HC-CH=ddot (O) B H_(2)C=HC-CH=ddot (O) C H_(2)C-HC=c=ddot (O) D H_(2)C=c=c=ddot (o) A) A B) B C) C D) D E)Nose of them

The correct answer is C) $H_{2}C-HC=c=\ddot {O}$.<br /><br />The resonance contributor in this molecule is the double bond between the carbon and oxygen atoms. The double bond can be delocalized, meaning that the electrons in the bond can be shared between the two atoms. This delocalization of electrons leads to resonance, which is a way to describe the distribution of electrons in a molecule.<br /><br />In this molecule, the double bond between the carbon and oxygen atoms can be represented as $H_{2}C-HC=c=\ddot {O}$. This representation shows that the double bond is delocalized between the carbon and oxygen atoms, leading to resonance.<br /><br />The other options do not correctly represent the resonance contributor in this molecule. Option A) $H_{2}C-HC-CH=\ddot {O}$ does not show the double bond between the carbon and oxygen atoms. Option B) $H_{2}C=HC-CH=\ddot {O}$ does not show the double bond between the carbon and oxygen atoms. Option D) $H_{2}C=c=c=\ddot {o}$ does not correctly represent the resonance contributor in this molecule.