The hybridization of carbon atoms 1,2, and 3 in the following respectively H_(2)C=CH-CH_(3) 1 2 3 A- sp, sp, and sp^2 B- sp,sp, and sp3 C- sp2,sp2 and sp3 D- sp^2,sp^3 , and sp^3 i. C ii. D iii. A iv. B

The correct answer is option C: $sp^2$, $sp^2$, and $sp^3$.<br /><br />In the given molecule $H_2C=CH-CH_3$, the carbon atoms are bonded as follows:<br /><br />1. Carbon atom 1 is bonded to two hydrogen atoms and one carbon atom, forming a double bond with the second carbon atom. This indicates that the hybridization of carbon atom 1 is $sp^2$.<br /><br />2. Carbon atom 2 is bonded to one hydrogen atom, one carbon atom, and one double-bonded carbon atom. This indicates that the hybridization of carbon atom 2 is also $sp^2$.<br /><br />3. Carbon atom 3 is bonded to three hydrogen atoms, indicating that the hybridization of carbon atom 3 is $sp^3$.<br /><br />Therefore, the correct answer is option C: $sp^2$, $sp^2$, and $sp^3$.