15. How https://www.kompara.com/marks) redox equation is balanced A) 2,6 B) 3,6 NO_(3)^-(aq)+Ni(s)arrow NO(g)+Ni^2+(aq) ard herg Na_(2)CO_(3) net ionic have a great programment C) D) E) 18. The titration of 10.00 mL of HCl solution of unknown concentration requires 12.54 mL of a 0.100 M NaOH solution to reach the equivalence A) 0.278 M B) 0 HCl(aq)+NaOH(aq)arrow H2O(l)+NaCl(aq) SM ) D) 0.143 M 19. How many milliliters of 0.260MNa_(2)S are needed to react with 35.00 mL of 0.315MAgNO_(3) according to the following unbalanced precipitation react with Na_(2)S(aq)+AgNO_(3)(aq)arrow NaNO_(3)(aq)+Ag_(2)S(s) B)57.8mL E) 0.0125 M A) 21.2 mL C) 42.4 mL D) 84.8 mL 20. Determine the theoretical yield of H_(2)S (in moles) if 32 mol Al_(2)S_(3) and 32 mol H_(2)O are reacted according to the following balanced E) 35.6 mL Al_(2)S_(3)(s)+6H_(2)O(l)arrow 2Al(OH)_(3)(s)+3H_(2)S(g) 16molH_(2)S B)96molH_(2)S C)48molH_(2)S D) 32molH_(2)S E) 64molH_(2)S 21. How many grams of NaCl are required to make 250.00 mL of a 3.000 M solution? (Na:22.99g/mol, 35.45g/mol) A) 58.40 g B) 43.83 g C) 175.3 g D) 14.60 g E) 1288 22. What is the concentration of a solution prepared by diluting 20.0 mL of a 0.200MLiCl to 250.0 mL A) 0.0160 M B) 0.160 M C) 2.50 M D) 0.00800 M E) 0.0320 M 23. What is the oxidation :tate of H in H_(2)(g) in th: following belanced reaction? Mg(s)+2HBr(aq)arrow MgBr_(2)(aq)+H_(2)(g) A) +1 B) +2 C) 0 D) -1 E) -2 4. What is the oxidizing agent in the following reaction? 2Al^3+(aq)+2Fe(s)arrow 2Al(s)+3Fe^2+(aq) A) Al^3+ B) Fe C) Al D) Fe^2+ E) none 5. Determine the limiting reactant (LR) and the mass (ing) of nitrogen that can be formed from 50. N_(2)O_(4) and 45.0 g N_(2)H_(4) from the unbalanced reaction given below. Some possibly useful atomi and molar masses are as follows: N=14.01g/mol H=1.008g/mol,O=16.000g/mol,N_(2)O_(4)=92.02g/mol,N_(2)H_(4)=32.05g/mol N_(2)O_(4)(l)+N_(2)H_(4)(l)arrow N_(2)(g)+H_(2)O(g) A) LR=N_(2)H_(4),59.0gN_(2) formed B LR=N_(2)O_(4),45.7gN_(2) formed C) LR=N_(2)H_(4),13.3gN_(2) formed D LR=N_(2)O_(4),105gN_(2)formed E) No LR, 45 .0 g

Let's go through each question and provide the correct answers:<br /><br />15. How to balance the redox equation:<br />The correct answer is B) 3,6. To balance the redox equation, you need to balance the atoms involved in the oxidation and reduction reactions separately. In this case, the equation is:<br />$NO_{3}^{-}(aq) + 3Ni(s) \rightarrow 2NO(g) + 3Ni^{2+}(aq)$<br /><br />17. Net ionic equation for $Na_{2}CO_{3}$:<br />The correct answer is C) $Na^{+}(aq) + CO_{3}^{2-}(aq) \rightarrow Na^{+}(aq) + CO_{3}^{2-}(aq)$<br /><br />18. Concentration of $HCl$ solution:<br />The correct answer is D) 0.143 M. To find the concentration of the $HCl$ solution, you can use the formula:<br />$C_{1}V_{1} = C_{2}V_{2}$<br />where $C_{1}$ is the concentration of the $NaOH$ solution, $V_{1}$ is the volume of the $NaOH$ solution, $C_{2}$ is the concentration of the $HCl$ solution, and $V_{2}$ is the volume of the $HCl$ solution.<br />Plugging in the values, we get:<br />$0.100 \times 12.54 = 0.143 \times 10.00$<br />Solving for $C_{2}$, we find that the concentration of the $HCl$ solution is 0.143 M.<br /><br />19. Volume of $Na_{2}S$ needed to react with $AgNO_{3}$:<br />The correct answer is B) 57.8 mL. To find the volume of $Na_{2}S$ needed to react with $AgNO_{3$, you can use the formula:<br />$M_{1}V_{1} = M_{2}V_{2}$<br />where $M_{1}$ is the molarity of the $Na_{2}S$ solution, $V_{1}$ is the volume of the $Na_{2}S$ solution, $M_{2}$ is the molarity of the $AgNO_{3}$ solution, and $V_{2}$ is the volume of the $AgNO_{3}$ solution.<br />Plugging in the values, we get:<br />$0.260 \times V_{1} = 0.315 \times 35.00$<br />Solving for $V_{1}$, we find that the volume of $Na_{2}S$ needed is 57.8 mL.<br /><br />20. Theoretical yield of $H_{2}S$:<br />The correct answer is B) 96 mol $H_{2}S$. To find the theoretical yield of $H_{2}S$, you can use the stoichiometry of the balanced equation:<br />$Al_{2}S_{3}(s) + 6H_{2}O(l) \rightarrow 2Al(OH)_{3}(s) + 3H_{2}S(g)$<br />From the balanced equation, we can see that 1 mole of $Al_{2}S_{3}$ reacts with 6 moles of $H_{2}O$ to produce 3 moles of $H_{2}S$. Therefore, if we have 32 moles of $Al_{2}S_{3}$ and 32 moles of $H_{2}O$, the limiting reactant is $H_{2}O$ and the theoretical yield of $H_{2}S$ is 96 mol.<br /><br />21. Mass of $NaCl$ needed to make a solution:<br />The correct answer is C) 175.3 g. To find the mass of $NaCl$ needed to make a 250.00 mL solution with a concentration of 3.000 M, you can use the formula:<br />$M = \frac{g}{V}$<br />where $M$ is the molarity, $g$ is the mass of the solute, and $V$ is the volume of the solution.<br />Plugging in the values, we get:<br />$3.000 = \frac{g}{250.00}$<br />Solving for $g$, we find that the mass of $NaCl$ needed is 175.3 g.<br /><br />22. Concentration of a diluted solution:<br />The correct answer is A) 0.0160 M. To find the concentration of a solution prepared by diluting 20.0 mL of a 0.200 M $LiCl$ solution to 250.0 mL, you can use the formula:<br />$C_{1}V_{1} = C_{2}V_{2}$<br />where $C_{1}$ is the initial concentration, $V_{1}$ is the