A hypothetical element, E, has two stable isotopes. E-38=38.012 u 75.68% E-46=45.981u 24.32% The element's atomic mass would be closest to which of the elements? i) K ii) Ar iii ) Ca iv ) Sc v) Cl a. iii b. ii C. V d. i e. iV

To find the atomic mass of the hypothetical element E, we need to calculate the weighted average of the atomic masses of its isotopes.<br /><br />The atomic mass of E can be calculated using the formula:<br /><br />Atomic mass of E = (fractional abundance of isotope 1 × atomic mass of isotope 1) + (fractional abundance of isotope 2 × atomic mass of isotope 2)<br /><br />Given:<br />Isotope E-38 has an atomic mass of 38.012 u and accounts for 75.68% of the total abundance.<br />Isotope E-46 has an atomic mass of 45.981 u and accounts for 24.32% of the total abundance.<br /><br />Substituting the values into the formula:<br /><br />Atomic mass of E = (0.7568 × 38.012) + (0.2432 × 45.981)<br /><br />Calculating the values:<br /><br />Atomic mass of E = 28.683 + 11.188<br /><br />Atomic mass of E = 39.871<br /><br />Therefore, the atomic mass of the hypothetical element E is approximately 39.871.<br /><br />Comparing this value with the atomic masses of the given elements:<br /><br />i) K (Potassium) has an atomic mass of approximately 39.098.<br />ii) Ar (Argon) has an atomic mass of approximately 39.948.<br />iii) Ca (Calcium) has an atomic mass of approximately 40.078.<br />iv) Sc (Scandium) has an atomic mass of approximately 44.96.<br />v) Cl (Chlorine) has an atomic mass of approximately 35.45.<br /><br />The atomic mass of E (39.871) is closest to the atomic mass of K (Potassium), which is approximately 39.098.<br /><br />Therefore, the correct answer is option d. i.