The chlorine present in PVC has two stable isotopes: {}^35Cl with a mass of 34.97 amu and 75.77% abundance; and {}^37Cl with a mass of 36.95 amu. What is the atomic mass of chlorine?

To find the atomic mass of chlorine, we need to calculate the weighted average of the masses of the two stable isotopes based on their abundances.<br /><br />Given:<br />- ${}^{35}Cl$ has a mass of 34.97 amu and an abundance of 75.77%.<br />- ${}^{37}Cl$ has a mass of 36.95 amu.<br /><br />The atomic mass of chlorine can be calculated using the formula:<br /><br />Atomic mass of chlorine = (Mass of ${}^{35}Cl$ × Abundance of ${}^{35}Cl$) + (Mass of ${}^{37}Cl$ × Abundance of ${}^{37}Cl$)<br /><br />Substituting the given values:<br /><br />Atomic mass of chlorine = (34.u0.7570) + (36.95 amu × 0.2423)<br /><br />Atomic mass of chlorine = 26.51 amu + 8.92 amu<br /><br />Atomic mass of chlorine = 35.43 amu<br /><br />Therefore, the atomic mass of chlorine is approximately 35.43 amu.