Element: Mg of Atoms:1 Element: CI of Atoms: 2 gram formula weight (g):95.21 Compound Formula: C_(6)H_(12)O_(6) Element: C of Atoms: square Element: H of Atoms: square : Element: 0 of Atoms: square gram formula weight (g): square Assignment -12. How Big Is a Mole? Avogadro's Number

Let's break down the information and fill in the blanks step by step.<br /><br />1. **Compound Formula: \(C_{6}H_{12}O_{6}\)**<br /><br /> - Element: C (Carbon)<br /> - Number of Atoms: 6<br /> - Element: H (Hydrogen)<br /> - Number of Atoms: 12<br /> - Element: O (Oxygen)<br /> - Number of Atoms: 6<br /><br />2. **Gram Formula Weight Calculation for \(C_{6}H_{12}O_{6}\):**<br /><br /> To calculate the gram formula weight (molar mass) of \(C_{6}H_{12}O_{6}\), we need to sum up the atomic masses of all the atoms in the compound. The atomic masses are approximately:<br /> - Carbon (C): 12.01 g/mol<br /> - Hydrogen (H): 1.01 g/mol<br /> - Oxygen (O): 16.00 g/mol<br /><br /> Now, calculate the total molar mass:<br /> \[<br /> \text{Molar Mass} = (6 \times 12.01) + (12 \times 1.01) + (6 \times 16.00)<br /> \]<br /> \[<br /> = 72.06 + 12.12 + 96.00<br /> \]<br /> \[<br /> = 180.18 \text{ g/mol}<br /> \]<br /><br />So, the completed information is:<br /><br />- Compound Formula: \(C_{6}H_{12}O_{6}\)<br /> - Element: C<br /> - Number of Atoms: 6<br /> - Element: H<br /> - Number of Atoms: 12<br /> - Element: O<br /> - Number of Atoms: 6<br /> - Gram Formula Weight (g): 180.18<br /><br />3. **Assignment - How Big Is a Mole? Avogadro's Number**<br /><br />Avogadro's number is \(6.022 \times 10^{23}\). This number represents the number of atoms, molecules, or particles in one mole of a substance. It is a fundamental constant in chemistry used to convert between the number of particles and the amount of substance in moles.