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sqrt (7+2sqrt (x))=5 epicigin segilayan x cledged applicakilerdes angisidir? A. 49 B) 54 cier D) 100 E) to

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sqrt (7+2sqrt (x))=5
epicigin segilayan x cledged applicakilerdes
angisidir?
A. 49
B) 54
cier
D) 100
E) to

sqrt (7+2sqrt (x))=5 epicigin segilayan x cledged applicakilerdes angisidir? A. 49 B) 54 cier D) 100 E) to

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İbrahim
Kıdemli · 11 yıl öğretmeni
Uzman doğrulaması

Cevap

To solve the equation \(\sqrt{7 + 2\sqrt{x}} = 5\), we can start by squaring both sides to eliminate the square root:<br /><br />\[<br />(\sqrt{7 + 2\sqrt{x}})^2 = 5^2<br />\]<br /><br />This simplifies to:<br /><br />\[<br />7 + 2\sqrt{x} = 25<br />\]<br /><br />Next, we isolate the term with the square root:<br /><br />\[<br />2\sqrt{x} = 25 - 7<br />\]<br /><br />\[<br />2\sqrt{x} = 18<br />\]<br /><br />Now, divide both sides by 2:<br /><br />\[<br />\sqrt{x} = 9<br />\]<br /><br />Finally, square both sides again to solve for \(x\):<br /><br />\[<br />x = 9^2<br />\]<br /><br />\[<br />x = 81<br />\]<br /><br />So, the correct answer is not listed among the options provided.
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