QUESTION 3/10 Find thearea (in square millimeters) of a right triangle with a leg of length 18 mm and a hypotenuse of length 80 mm. Enteranumber only (no units). Ifyour answer is not a whole number, then round to the nearest hundredth. 1 point Enteranswer here.

## Step 1<br />The problem involves finding the area of a right triangle. The formula for the area of a right triangle is given by:<br />### **Area = \(\frac{1}{2} \times \text{base} \times \text{height}\)**<br /><br />## Step 2<br />In this problem, the base and the height of the triangle are the two legs of the triangle. We are given that one leg (base) is 18 mm and the hypotenuse is 80 mm.<br /><br />## Step 3<br />We can use the Pythagorean theorem to find the length of the other leg (height). The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. Therefore, the length of the other leg can be calculated as:<br />### **Height = \(\sqrt{\text{Hypotenuse}^2 - \text{Base}^2}\)**<br /><br />## Step 4<br />Substituting the given values into the formula, we get:<br />### **Height = \(\sqrt{80^2 - 18^2}\)**<br /><br />## Step 5<br />Once we have the length of the other leg, we can substitute the values of the base and the height into the area formula to find the area of the triangle.