21) What is the molarity of sodium chloride in solution that is 13.0% by mass sodium chloride and that has a density of 1.10g/mL 7 A) 143 B) 2.45 C) 2.56 D) 2.23 E) 1.43times 10^-2 Answer:B

To find the molarity of sodium chloride in the solution, we need to follow these steps:<br /><br />1. Calculate the mass of sodium chloride in 1 liter of the solution.<br />2. Convert the mass of sodium chloride to moles.<br />3. Calculate the molarity using the formula: Molarity = moles of solute / liters of solution.<br /><br />Given information:<br />- The solution is 13.0% by mass sodium chloride.<br />- The density of the solution is 1.10 g/mL.<br /><br />Step 1: Calculate the mass of sodium chloride in 1 liter of the solution.<br />Density = 1.10 g/mL<br />Volume of the solution = 1 liter = 1000 mL<br />Mass of the solution = Density × Volume = 1.10 g/mL × 1000 mL = 1100 g<br />Mass of sodium chloride = 13.0% of 1100 g = 0.13 × 1100 g = 143 g<br /><br />Step 2: Convert the mass of sodium chloride to moles.<br />Molar mass of sodium chloride (NaCl) = 58.44 g/mol<br />Moles of sodium chloride = Mass of sodium chloride / Molar mass of sodium chloride<br />Moles of sodium chloride = 143 g / 58.44 g/mol = 2.44 mol<br /><br />Step 3: Calculate the molarity using the formula:<br />Molarity = Moles of solute / Liters of solution<br />Molarity = 2.44 mol / 1 L = 2.44 M<br /><br />Therefore, the molarity of sodium chloride in the solution is 2.44 M.<br /><br />The correct answer is B) 2.4 M.