Check Should 16.3 g of S contain fewer than Avogadro's number of atoms? What mass of S would contain Avogadro's number of atoms?

## Step 1<br />The problem involves the concept of Avogadro's number, which is a fundamental constant in chemistry. Avogadro's number, denoted as \(N\), is approximately \(6.022 \times 10^{23}\). This number represents the number of atoms in one mole of any substance.<br /><br />## Step 2<br />The molar mass of an element is the mass of one mole of that element. For sulfur (S), the molar mass is approximately 32 g/mol.<br /><br />## Step 3<br />To find out if 16.3 g of sulfur contains fewer than Avogadro's number of atoms, we need to compare the given mass with the molar mass of sulfur. Since 16.3 g is less than 32 g, it contains fewer than Avogadro's number of atoms.<br /><br />## Step 4<br />To find the mass of sulfur that contains Avogadro's number of atoms, we multiply the molar mass of sulfur by Avogadro's number. This gives us \(32 \times 6.022 \times 10^{23}\) g, which is approximately \(1.92 \times 10^{24}\) g.