1. What is the molarity of a solution that was prepared by dissolving 142 g of NaNO_(3) (molar mass=85.0g/mol) in enough water to make 350 mL of solution?

To find the molarity of the solution, we need to calculate the number of moles of $NaNO_{3}$ dissolved in the solution and then divide it by the volume of the solution in liters.<br /><br />Given information:<br />- Mass of $NaNO_{3}$ dissolved: 142 g<br />- Molar mass of $NaNO_{3}$: 85.0 g/mol<br />- Volume of the solution: 350 mL (0.35 L)<br /><br />Step 1: Calculate the number of moles of $NaNO_{3}$ dissolved.<br />Number of moles = Mass / Molar mass<br />Number of moles = 142 g / 85.0 g/mol = 1.67 mol<br /><br />Step 2: Calculate the molarity of the solution.<br />Molarity = Number of moles / Volume of the solution in liters<br />Molarity = 1.67 mol / 0.35 L = 4.77 M<br /><br />Therefore, the molarity of the solution is 4.77 M.