Refer to question #6 How many molecules of oxygen gas are in 50.0 L of oxygen gas? 5.51times 10^wedge 23molecules 6.02times 10^wedge 23molecules 1.34times 10^wedge 24molecules 2.69times 10^wedge 24molecules

To determine the number of molecules of oxygen gas in 50.0 L of oxygen gas, we can use the ideal gas law and Avogadro's number.<br /><br />First, recall that at standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. <br /><br />Given:<br />- Volume of oxygen gas = 50.0 L<br />- Molar volume at STP = 22.4 L/mol<br /><br />We can calculate the number of moles of oxygen gas using the formula:<br />\[ \text{Number of moles} = \frac{\text{Volume}}{\text{Molar volume}} \]<br /><br />\[ \text{Number of moles} = \frac{50.0 \, \text{L}}{22.4 \, \text{L/mol}} \approx 2.2321 \, \text{moles} \]<br /><br />Next, we use Avogadro's number to find the number of molecules. Avogadro's number is \(6.022 \times 10^{23}\) molecules per mole.<br /><br />\[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} \]<br /><br />\[ \text{Number of molecules} = 2.2321 \, \text{moles} \times 6.022 \times 10^{23} \, \text{molecules/mole} \]<br /><br />\[ \text{Number of molecules} \approx 1.34 \times 10^{24} \, \text{molecules} \]<br /><br />Therefore, the correct answer is:<br />\[ 1.34 \times 10^{24} \, \text{molecules} \]<br /><br />So, the correct option is:<br />\[ \boxed{1.34 \times 10^{24} \, \text{molecules}} \]