Give the hybridization of the central atom in the following species: ONBr square hybridization

To determine the hybridization of the central atom in the species ONBr, we need to consider the number of regions of electron density (bonds and lone pairs) around the central atom.<br /><br />In the case of ONBr, the central atom is nitrogen (N). Nitrogen has 5 valence electrons and forms 3 bonds with oxygen (O), bromine (Br), and another nitrogen (N). Additionally, there is 1 lone pair on the nitrogen atom.<br /><br />The total number of regions of electron density around the nitrogen atom is 4 (3 bonds and 1 lone pair).<br /><br />Based on the number of regions of electron density, we can determine the hybridization of the central atom:<br /><br />- 2 regions of electron density: sp<br />- 3 regions of electron density: sp2<br />- 4 regions of electron density: sp3<br />- 5 regions of electron density: sp3d<br />- 6 regions of electron density: sp3d2<br /><br />In this case, the nitrogen atom has 4 regions of electron density, so the hybridization is sp3.<br /><br />Therefore, the hybridization of the central atom in the species ONBr is sp3.