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Calculate the molar mass of KAl(SO_(4))_(2)cdot 12H_(2)O a. 560g/mole b. 320g/mole C. 410.76g/mole d. 474.38g/mole e. 280g/mole Clear my choice

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Calculate the molar mass of KAl(SO_(4))_(2)cdot 12H_(2)O
a. 560g/mole
b. 320g/mole
C. 410.76g/mole
d. 474.38g/mole
e. 280g/mole
Clear my choice

Calculate the molar mass of KAl(SO_(4))_(2)cdot 12H_(2)O a. 560g/mole b. 320g/mole C. 410.76g/mole d. 474.38g/mole e. 280g/mole Clear my choice

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To calculate the molar mass of $KAl(SO_{4})_{2}\cdot 12H_{2}O$, we need to find the atomic masses of each element in the compound and multiply them by their respective subscripts.<br /><br />The atomic masses are:<br />- Potassium (K): 39.10 g/mol<br />- Aluminum (Al): 26.98 g/mol<br />- Sulfur (S): 32.07 g/mol<br />- Oxygen (O): 16.00 g/mol<br />- Hydrogen (H): 1.01 g/mol<br /><br />Now, let's calculate the molar mass of each part of the compound:<br />- $KAl(SO_{4})_{2}$: <br /> - Potassium (K): $1 \times 39.10 = 39.10$ g/mol<br /> - Aluminum (Al): $1 \times 26.98 = 26.98$ g/mol<br /> - Sulfur (S): $2 \times 32.07 = 64.14$ g/mol<br /> - Oxygen (O): $8 \times 16.00 = 128.00$ g/mol<br /> - Total: $39.10 + 26.98 + 64.14 + 128.00 = 258.22$ g/mol<br /><br />- $12H_{2}O$:<br /> - Hydrogen (H): $12 \times 2 \times 1.01 = 24.24$ g/mol<br /> - Oxygen (O): $12 \times 16.00 = 192.00$ g/mol<br /> - Total: $24.24 + 192.00 = 216.24$ g/mol<br /><br />Finally, add the molar masses of both parts:<br />$258.22 + 216.24 = 474.46$ g/mol<br /><br />Therefore, the correct answer is:<br />d. $474.38g/mole$
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