Balance the following reaction A coefficient of "I"is understood. Choose option "blank" for the correct answer if the coefficient is "1." :(XOH+ +Cu(NO_(3))_(2)arrow +KNO_(3)+ +Cu(OH)_(2)

To balance the chemical equation, we need to ensure that the number of atoms of each element is equal on both sides of the equation. Let's go through the balancing process step by step:<br /><br />The unbalanced equation is:<br />\[ XOH + Cu(NO_3)_2 \rightarrow KNO_3 + Cu(OH)_2 \]<br /><br />1. **Identify the compounds and elements:**<br /> - Reactants: \( XOH \) (where X is a placeholder for an alkali metal), \( Cu(NO_3)_2 \)<br /> - Products: \( KNO_3 \), \( Cu(OH)_2 \)<br /><br />2. **Balance the copper (Cu) atoms:**<br /> - There is 1 Cu atom in \( Cu(NO_3)_2 \) and 1 Cu atom in \( Cu(OH)_2 \). Copper is already balanced.<br /><br />3. **Balance the nitrate (NO_3) groups:**<br /> - There are 2 nitrate groups in \( Cu(NO_3)_2 \) and 1 nitrate group in \( KNO_3 \).<br /> - To balance the nitrates, place a coefficient of 2 in front of \( KNO_3 \):<br /> \[ XOH + Cu(NO_3)_2 \rightarrow 2KNO_3 + Cu(OH)_2 \]<br /><br />4. **Balance the potassium (K) atoms:**<br /> - With the coefficient of 2 in front of \( KNO_3 \), there are now 2 K atoms needed.<br /> - Therefore, place a coefficient of 2 in front of \( XOH \) (assuming X = K):<br /> \[ 2KOH + Cu(NO_3)_2 \rightarrow 2KNO_3 + Cu(OH)_2 \]<br /><br />5. **Balance the hydroxide (OH) groups:**<br /> - There are 2 OH groups in \( 2KOH \) and 2 OH groups in \( Cu(OH)_2 \). Hydroxide is balanced.<br /><br />Now, the balanced equation is:<br />\[ 2KOH + Cu(NO_3)_2 \rightarrow 2KNO_3 + Cu(OH)_2 \]<br /><br />Thus, the coefficients are:<br />- \( KOH \): 2<br />- \( Cu(NO_3)_2 \): 1 (blank)<br />- \( KNO_3 \): 2<br />- \( Cu(OH)_2 \): 1 (blank)<br /><br />So, the correct answer is:<br />- \( KOH \): 2<br />- \( Cu(NO_3)_2 \): blank<br />- \( KNO_3 \): 2<br />- \( Cu(OH)_2 \): blank